We are back to the convention and
We wish to focus on irreducible polynomial representations of G.
The weak Peter-Weyl theorem gives:
Theorem. Restricting the RHS to only polynomial irreducible V gives us
on the LHS, where each polynomial
in
restricts to a function
Proof
Since is a matrix coefficient, we have
and this is clearly a
-submodule. Furthermore, as functions
, the
are algebraically independent over
by the main lemma here.
Since each is irreducible as a
-module,
corresponds to a direct sum
over some set S of G-irreps V. It remains to show that S is precisely the set of polynomial irreps.
Next, as -representations, we have a decomposition
into homogeneous components; each is a finite-dimensional representations of By considering the action of
, each component is a polynomial representation of G. Hence every irrep in S must be polynomial.
Conversely, if W is any polynomial irrep of G of dimension m, upon taking a basis the action of every can be written as an
matrix with entries in
Hence
contains W; since W is irreducible,
contains W. ♦
Decomposing By Degrees
Thus we have as isomorphism of -reps (*):
Definition. The degree of a polynomial irrep V is the unique
for which
contains it.
Let us pick one particular component We get a G-rep by taking the action of
Hence its Laurent polynomial can be computed by considering the action of
on it. Since the space is spanned by monomials of degree d, we have:
Property 1. For a polynomial G-irrep V, we have
Recall that if G acts on V, then acts on
via:
Hence, taking the dual gives:
Property 2. The action of
on
gives the character
The pair of diagonal matrices takes
. Hence, taking the basis of monomials of degree d, we have:
Property 3. The action of
on
has character:
Finally, from lemma 3 here and property 1 above, we see that:
Property 4. For each d, the number of polynomial G-irreps of degree d is exactly the cardinality of
Main Theorem
Now we are ready to prove:
Theorem. A polynomial representation V of G of degree d is irreducible if and only if
is a Schur polynomial in
of of degree d.
Proof
For each d, let be the polynomial irreps of degree d; let
a homogeneous symmetric polynomial in
of degree d. By property 2, the character of
on
is:
By property 3 and (*), summing this over all d and j gives the power series:
Finally by property 4, for each d, the number of is exactly the size of
Thus by the criterion for orthonormal basis proven (much) earlier, the
forms an orthonormal basis of
Hence, each
is, up to sign, a Schur polynomial of degree d. Since the coefficients of
are non-negative, they are the Schur polynomials. ♦
Summary
We have a correspondence between:
which takes Under this correspondence, for partition
,
Indeed, the first two correspondences are obvious; the third is what we just proved. The fourth is immediate from the definition of . The final correspondence follows from the third one. Denote
for the corresponding irrep of
; we can now port over everything we know about symmetric polynomials, such as:
Setting for
gives:
where is the number of SYT of shape
Unfortunately, the involution map does not have a nice interpretation in our context. (No it does not take the polynomial irrep to its dual!)